InterviewSolution
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InterviewSolution
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The area of cross-section of the wider tube shown in fig., is `800cm^(2)` . If a mass of 12 kg is placed on the massless piston, what is the difference in the level of water in two tubes. |
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Answer» Here, `A= 800 cm^(2) ` , `F= mg = (12 xx 1000 xx 980) dyn es`. Thus, pressure on the liquid, `p= F/A = (12 xx 1000 xx 980)/(800) dyn e//cm^(2)` If h is the difference in level of liquid in the two tubes then, `p = h rho g = hxx 1 xx 980` `:. h xx 1 xx 980 = (12 xx10 xx 980)/(800)` or, ` h=15.0 cm`. |
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