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    				| 1. | The area of the circle centred at (1,2) and passing through (4,6) isA. `5pi` sq unitB. `5pi` sq unitC. `5pi` sq unitD. None of the above | 
| Answer» Correct Answer - D The equation of a circle centred at (1,2) and passing through (4,6) is `(x-1)^(2)+(y-2)^(2)=(4-1)^(2)+(6-2)^(2)` `Rightarrow x^(2)+y^(2)-2x-4y+1+4=9+16` `Rightarrow x^(2)+y^(2)-2x-4y-20=0` Now, radius `=sqrt((-1)^(2)+(-2)^(2)+20)` `=sqrt(1+4+20)=5` `therefore ` Area of circle `=pir^(2)` `=25pi"sq unit"` | |