1.

The audible frequency for a normal human being is `20 Hz` to `20 kHz`. Fuind the corresponding wavelengths if the speed of sound in air `320 m//s`. (b) Find the phase difference between two position separated by `20 cm` at a particular instant.

Answer» Correct Answer - `16 mm, 16 m`
`lambda = (V)/(eta)`
`lambda_(max) = (320)/(20 Hz) = 16 m , lambda_(min) = (320)/(20 KHz) = 16 mm`.


Discussion

No Comment Found

Related InterviewSolutions