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The average age of 10 students is 6 years. The sum of ages of 9 of them is 52 years. Find the age of 10th student. |
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Answer» Let the sum of ages of 10 boys = x no of boys = 10 average = \(\cfrac{x}{10}\) 6 = \(\cfrac{x}{10}\) x = 60 (sum of ages of all boys) sum of ages of a boy = 52 Let the age of 10th student = y sum of ages of a boys = x - y 52 = 60 - y y = 8 \(\therefore\) Age of 10th student = 8 years |
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