1.

The average age of 10 students is 6 years. The sum of ages of 9 of them is 52 years. Find the age of 10th student.

Answer»

Let the sum of  ages of 10 boys = x

no of boys = 10

average = \(\cfrac{x}{10}\)

6 = \(\cfrac{x}{10}\)

x = 60 (sum of ages of all boys)

sum of ages of a boy = 52

Let the age of 10th student = y

sum of ages of a boys = x - y

52 = 60 - y

y = 8

\(\therefore\) Age of 10th student = 8 years



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