1.

The average force rn(1) 25 Necessary to stop a hammer having momentum 25 N-s in 0.05 second is-(2) 50 N(3) 1.25 N(4) 500 N

Answer»

Force, F = rate of change of momentum

F = P/t

where P is change of momentum in time t

or F = 25/0.050 = 500 N



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