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The average magnitude of force necessary to stopa hammer moving with 30 Ns momentum in 0.5 sis(2) 10 N(3) 30 N(4) Infiniteau |
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Answer» Force = momentum /timeMomentum = 30 Ns, time =.5 s Force = 30/.5 = 300/5 = 60 N Correct option is (1) |
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