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The average value of current I= (4t^2) A from t=0 to t=4 isa)64/3 Ab)2Ac)8/5Ad)9A |
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Answer» Answer: a) 64/3 A Explanation: Refer to the image of the explanation. Hope it helps. If so, then PLEASE MAKE me as BRAINLIEST answer. Thank you Thanks Rate⭐⭐⭐⭐⭐ |
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