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The average velocity of a body moving with uniform acceleration after travelling a distance of `3.06 m` is `0.34 m s^(-1)`. If the change in velocity of the body is `0.18 ms^(-1)` during this time, its uniform acceleration is .A. 0.01B. 0.2C. 0.03D. 0.04 |
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Answer» Correct Answer - B `t=("distance")/(V_(ave)),a=("change in velocity")/("total time")=(v-u)/(t)` |
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