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The axes of the two shafts are intersecting and are at 35° to each other. These two shafts are connected by Hook’s joint. At which position of the drives shaft acceleration will be maximum?(a) 68.4°(b) 96.1°(c) 225.5°(d) 330.7°The question was asked in exam.I would like to ask this question from Universal Joints and Differential in division Chassis & Transmission System of Automobile Engineering

Answer»

Right answer is (C) 225.5°

Explanation: (ωB / ωA) = (cos α) / (1 – cos^2θ sin^2α) where A = driving shaft and B = driven shaft and α is the ANGLE between shaftA and shaft B. θ is the angle through which the shaft A rotates. Acceleration will be maximum when cos2θ = (2 sin^2α) / (2 – sin^2α) =(2 sin^240°) / (2 – sin^240°) = 0.5207 i.e. 2θ = 58.62i.e. θ = 29.31°, 180° – 29.31° = 150.69°, 180° + 29.31° = 209.31°, 360° – 29.31° = 330.69°


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