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The bacteria in a culture grows by 10% in the first hour, decreases by 10% in the second hour and again increases by 10% in the third hour. If the original count of the bacteria in a sample is 10000, find the bacteria count at the end of 3 hours. (a) 13310 (b) 10890 (c) 10990 (d) 11000 |
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Answer» (b) 10890 Bacteria count after 3 years = 10000\(\big(1+\frac{10}{100}\big)\)\(\big(1-\frac{10}{100}\big)\)\(\big(1+\frac{10}{100}\big)\) = 10000 x \(\frac{11}{10}\)x \(\frac{9}{10}\)x \(\frac{11}{10}\) = 10890. |
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