The `beta`-decay process, discovered around `1900`, is basically the decay of a neutron `(n)`, In the laboratory, a proton `(p)` and an electron `(e^(-))` are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a tro-body dcay process, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process i.e., `n rarr p + e^(-)+overset(-)v_(e )`, around `1930`, Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino `(overset(-)V_(e ))` to be massless and possessing negligible energy, and neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is `0.8xx10^(6)eV`. The kinetic energy carried by the proton is only the recoil energy. What is the maximum energy of the anti-neutrino?A. zeroB. Much less than `0.8xx10^(6)eV`C. Nearly `0.8xx10^(6)eV`D. Much larger than `0.8xx10^(6)eV`

The `beta`-decay process, discovered around `1900`, is basically the d

1.	The `beta`-decay process, discovered around `1900`, is basically the decay of a neutron `(n)`, In the laboratory, a proton `(p)` and an electron `(e^(-))` are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a tro-body dcay process, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process i.e., `n rarr p + e^(-)+overset(-)v_(e )`, around `1930`, Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino `(overset(-)V_(e ))` to be massless and possessing negligible energy, and neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is `0.8xx10^(6)eV`. The kinetic energy carried by the proton is only the recoil energy. What is the maximum energy of the anti-neutrino?A. zeroB. Much less than `0.8xx10^(6)eV`C. Nearly `0.8xx10^(6)eV`D. Much larger than `0.8xx10^(6)eV`
Answer» Correct Answer - C `KE_(max)="of"beta^(-)` `Q=0.8xx10^(6)eV` `KE_(P)+KE_(beta^(-))+KE_(overset(-)v)=Q` `KE_(P)` is almost zero When `KE_(beta^(-))=0` then `KE_(overset(-)v)=Q-KE_(P)` `~=Q`

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