InterviewSolution
Saved Bookmarks
| 1. |
The binding energies per nucleon for deuteron (`_1H^2`) and helium (`_2He^4) are 1.1 MeV and 7.0 MeV respectively. The energy released when two deuterons fuse to form a helium nucleus (`_2He^4`) is…….. |
|
Answer» Correct Answer - B::C `2_1H^2rarr_2He^4` Binding energy of two deuterons, `E_1=2[2xx1.1]=4.4 MeV` Binding energy of helium nucleus, `E_2=4(7.0)=28.0 MeV` `:.` Energy released `Delta E=E_2-E_1` `=(28-4.4)MeV=23.6 MeV` |
|