1.

The binding energies per nucleon for deuteron (`_1H^2`) and helium (`_2He^4) are 1.1 MeV and 7.0 MeV respectively. The energy released when two deuterons fuse to form a helium nucleus (`_2He^4`) is……..

Answer» Correct Answer - B::C
`2_1H^2rarr_2He^4`
Binding energy of two deuterons,
`E_1=2[2xx1.1]=4.4 MeV`
Binding energy of helium nucleus,
`E_2=4(7.0)=28.0 MeV`
`:.` Energy released `Delta E=E_2-E_1`
`=(28-4.4)MeV=23.6 MeV`


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