1.

The blood output from the human cardiac is about 5X 10-3 m3/minute andradius of aorta is 10-2 m. find the average velocity of flow in the aorta.​

Answer»

Explanation:

RATE of flow = Velocity × AREA

  • Rate of flow = 5 × 10-³ m³/ min
  • Radius = 10-² m
  • Area =

5 \times {10}^{ - 3} = <klux>V</klux> \: \times \pi \: {( {10}^{ - 2} )}^{2}

v = 5 \times {10}^{ - 3}/\pi \: {( {10}^{ - 2} )}^{2}

v = 5 \times {10}^{ - 3}/ 3.14× {( {10}^{ - 2} )}^{2}

v = 15.9 m/min


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