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The brakes applied to a car produce an acceleration of 6 ms^(-2)in the opposite direction to the motion. If the car takes 2 s to stop after the application of brakes, calculate the distance traveled during this time. |
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Answer» Solution :We have been given `a=-6ms^(-2)`, t=2s and v=0 From the equation of motion, v=u+at 0=u+(-6 X 2 ) 0= u -12 `therefore u=12 MS^(-1)` `s=ut+1//2 at^2` `=(12 xx 2) +1//2 (-6 xx 2 xx 2)` =24-12 = 12 m Thus, the CAR will move 12 m before it STOPS after the application of brakes . |
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