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The capacitor C is initially without charge. X is now joined to Y for a long time, during which `H_1` heat is produced in the resistance R. X is now joined to Z for a long time, during which `H_2` heat is produced in R A. `H_1 = H_2`B. `H_1 = (1)/(2)H_2`C. `H_1 = 2H_2`D. The maximum energy stored in C at any time is `H_1.` |
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Answer» Correct Answer - A::D When X is joined to Y for a long time (charging), energy stored in the capacitor is equal to heat produced in `R =H_(1)`. When X is joined to Z (discharging), the energy stored in `C = (H_(1))` reappears as heat `(H_(2))` in R. Thus, `H_(1) = H_(2)`. |
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