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In the circuit shown in figure find: a. the current in the `3.00 Omega` resistor,b. the unknown emfs`E_1` and `E_2` and c the resistance `R`. |
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Answer» a. The sum of the currents that enter the junction below the resistor equals `3A + 5A = 8A` b. Using the lower left loop, we get `epsilon _(1) - (4Omega)(3A)- (3Omega)(8A) = 0 or epsion_(1) = 36V` Using the lower right loop , we get `epsilon - (6Omega)(5A) - (3Omega)(8A) = 0` or `epsilon_2 =54V` c. Using the top loop, we get `54 V-R(2A) - 36 V = 0` or `R(18V)/(2A) = 9Omega` |
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