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InterviewSolution
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The massses of the three wires of copper are in the ratio 1 : 3 : 5. And their lengths are in th ratio 5 : 3 : 1. the ratio of their electrical resistance isA. `1:03:05`B. `5:03:01`C. `1 : 15 : 125`D. `125 : 15 : 1` |
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Answer» Correct Answer - D `R = (rhol)/(A) = (rhol^(2))/(Al) = (rhol^(2))/(V) = (rhol^(2))/(m//d) = (rhodl^(2))/(m) or R prop (l^(2))/(m)` `R_(1) : R_(2) : R_(3) = (l_(0)^(2))/(m_(1)): (l_(1)^(2))/(m_(2)) : (l_(3)^(2))/(m_(3)) = (25)/(1) : (9)/(3) : (1)/(5) = 125 : 15 : 1` |
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