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The current through the `8Omega` resistor (shown in fig.) is A. 4AB. 2AC. zeroD. 2.5A |
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Answer» Correct Answer - C The lower limit is zero volt (0 V) when X is at the lower end of the `4 k Omega` resistor. The upper limit is the potential differnece across the `4 k Omega` resistor when X is at the upper end of the `4 k Omega` resistor. That is `V= ((25)/(1K + 4K))4K = ((25)/(5)) 4 = 20V` Thus, the limits are 0 and 20 V. |
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