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The capacitor of capacitance `4 muF` and `6 muF` are connected in series. A potential difference of `500` volts applied to the outer plates of the two capacitor system. Then the charge on each capacitor is numericallyA. `6000 C`B. `1200 C`C. `1200 muC`D. `6000 muC` |
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Answer» Correct Answer - C `C_(eq) = (C_(1)C_(2))/(C_(1) + C_(2)) = 2.4 muF`. Charge flown `= 2.4 xx 500 xx 10^(-6) C = 1200 muC`. |
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