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The car moves with the speed 60kmph for 1hour in east direction and with same speed for 30 min in South direction. The displacement of car from initial position is |
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Answer» Answer: 10√45 km Explanation: Distance covered in East x = Speed × Time = 60 kmph × 1 HR = 60 km Distance covered in South y = Speed × Time = 60 kmph × 30 min = 60 kmph × 0.5 hr = 30 km East and South are perpendicular directions. So, displacement (shortest distance between INITIAL and FINAL position) of CAR (from Pythagoras theorem) is D = √(x² + y²) = √(60² + 30²) km = √(3600 + 900) km = √4500 km = 10√45 km |
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