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    				| 1. | The cartesian equation of a line is `(x - 6) /(2) = ( y + 4)/(7) = (z -5)/(3)` , find its vector equation . | 
| Answer» Equation of line `(x-6)/(2)=(y+4)/(7)=(z-5)/(3)` `therefore `The line is passing through the point `(6,-4,5)` and having direction ratios `2, 7, 3.` `"so "veca=6hati - 4hatj+5hatk` `"and "vec b=2hati+7hatj+3hatk` `therefore "The vector eqaution of line is " vecr=veca+lambda vecb` `rarr vecr = (6hati-4hatj+5hatk)+lambda(2hati+7hatj+3hatk)` | |