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The catalytic decomposition of `H_(2)O` was studied by titrating it at different intervals with `KMnO_(4)` and the following data were obtained : `{:("t (second)",0,600,1200),("V of KMmO"_(4)(mL)",22.8,13.8,8.3):}` Calculate the velocity constant for the reaction assuming it to be a first order reaction.

Answer» Correct Answer - `8.4xx10^(-3)s^(-1)`
Volume of `KMnO_(4)` used `prop` concentration of `H_(2)O_(2)`
Hence, `k=(2.303)/(t)log_(10).(V_(0))/(v_(t))`


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