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The circuit shown in figure has a load equivalent to _________(a) \(\frac{4}{3}\) Ω(b) \(\frac{8}{3}\) Ω(c) 4 Ω(d) 2 ΩI got this question by my school principal while I was bunking the class.My doubt is from Advanced Problems on Superposition Theorem topic in chapter Useful Theorems in Circuit Analysis of Network Theory

Answer»

Right option is (b) \(\FRAC{8}{3}\) Ω

To explain I would SAY: USING Superposition Theorem, in the given circuit, \(\frac{V}{4} + \frac{V-2I}{2}\) = I

Or, \(\frac{3V-4I}{4}\) = I

Or, 3V = 8I

∴ \(\frac{V}{I} = \frac{8}{3}\) Ω.



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