The circumference of the base of a cylinder is 88 cm and its height is

1.	The circumference of the base of a cylinder is 88 cm and its height is 15 cm. Find its curved surface area and total surface area.
Answer» Given, Circumference of base of cylinder = 88 cm Height of cylinder = 15 cm So, = 2πr = 88 Given = r = \(\frac{88}{2π}\) = \(\frac{88\times 7}{2\times 22}\) = 14 cm Radius of cylinder = 14 cm ∴ Curved surface area of cylinder = 2πrh = 2 x \(\frac{22}{7}\) x 14 x 15 = 1320 cm² ∴ Total surface area of cylinder = 2πr(h + r) = 2 x \(\frac{22}{7}\) x 14 x 29 = 2552 cm²

The circumference of the base of a cylinder is 88 cm and its height is 15 cm. Find its curved surface area and total surface area.

Answer»

Given,

Circumference of base of cylinder = 88 cm

Height of cylinder = 15 cm

So,

= 2πr = 88 Given

= r = \(\frac{88}{2π}\) = \(\frac{88\times 7}{2\times 22}\) = 14 cm

Radius of cylinder = 14 cm

∴ Curved surface area of cylinder = 2πrh = 2 x \(\frac{22}{7}\) x 14 x 15 = 1320 cm²

∴ Total surface area of cylinder = 2πr(h + r) = 2 x \(\frac{22}{7}\) x 14 x 29 = 2552 cm²