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The clutch plate has 160 mm inside and 240 mm outside diameter. The total force provided by the springs is 5 kN, when the clutch is new. The coefficient of friction is 0.4. What is the torque transmitted?(a) 300 Nm(b) 350 Nm(c) 400 Nm(d) 450 NmI had been asked this question during an online exam.The origin of the question is Transmission System in chapter Chassis & Transmission System of Automobile Engineering |
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Answer» RIGHT answer is (c) 400 NM For EXPLANATION: inside RADIUS = 80 mm, outside radius = 120 mm ⇒ Effective mean radius = R = (80 + 120) / 2 = 100 mm. Let W = 5 kN = 5000 N and μ = coefficient of friction = 0.4. Torque transmitted = 2 * μ * W * R = 2 * 0.4 * 5000 * 100 = 400 * 10^3 Nmm = 400 Nm. |
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