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The co-ordinates of the vertices of a side of square are (4, –3) and (–1, –5). Its area is(a) 2 √29 sq. units (b) \(\frac{\sqrt{89}}{2}\) sq. units (c) 89 sq. units (d) 29 sq. units |
Answer» (d) 29 sq. units Length of a side of the square = \(\sqrt{(-1-4)^2+(-5+3)^2}\) = \(\sqrt{25+4} = \sqrt{29}\) units. ∴ Area = (Side)2 = \((\sqrt{29})^2\) sq. units = 29 sq. units |
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