1.

The co-ordinates of the vertices of a side of square are (4, –3) and (–1, –5). Its area is(a) 2 √29 sq. units (b) \(\frac{\sqrt{89}}{2}\) sq. units (c) 89 sq. units (d) 29 sq. units

Answer»

(d) 29 sq. units

Length of a side of the square 

\(\sqrt{(-1-4)^2+(-5+3)^2}\)

\(\sqrt{25+4} = \sqrt{29}\) units.

∴ Area = (Side)2\((\sqrt{29})^2\) sq. units

= 29 sq. units



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