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The coefficient of friction between the tyres and road is 0.4. The minimum distance covered before attaining a speed of `8 ms^(-1)` starting from rest is nearly ( take `g=10 ms^(-2)`)A. 8mB. 4mC. 10mD. 16m |
Answer» Correct Answer - A (d) Retardation, `a=(mu mg)/(m)=mug=4ms^(-2)` using, `v^(2)=u^(2)+2as` `(8)^(2)=(0)^(2)+2(4)(s)` `therefore s=8m` |
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