The coefficient of performance of a Carnot refrigerator is 4. If the t

1.	The coefficient of performance of a Carnot refrigerator is 4. If the temperature of the hot reservoir is 47 °C, find the temperature of the cold reservoir.
Answer» Data : K = 4, T_H = 47°C = (273 + 47) K = 320 K = \(\frac{T_C}{T_H-T_C}\) = \(\frac{(4)((320)}{1+4}\)K = (0.8)(320)K = 256K = (256 – 273)°C = – 17°C This is the temperature of the cold reservoir. [Note : A hot-air type engine consisting of two cylinders, was developed by Robert Stirling (1790 -1878), a Scottish engineer and clergyman. He developed the concept in 1816 and obtained a patent for his design in 1827. Some engines were made in 1844. He also used helium and hydrogen in some engines developed thereafter. Stirling engines are used in submarines and spacecrafts.]

The coefficient of performance of a Carnot refrigerator is 4. If the temperature of the hot reservoir is 47 °C, find the temperature of the cold reservoir.

Answer»

Data : K = 4, T_H = 47°C = (273 + 47) K = 320

K = \(\frac{T_C}{T_H-T_C}\) = \(\frac{(4)((320)}{1+4}\)K = (0.8)(320)K

= 256K = (256 – 273)°C = – 17°C

This is the temperature of the cold reservoir.

[Note : A hot-air type engine consisting of two cylinders, was developed by Robert Stirling (1790 -1878), a Scottish engineer and clergyman. He developed the concept in 1816 and obtained a patent for his design in 1827. Some engines were made in 1844. He also used helium and hydrogen in some engines developed thereafter. Stirling engines are used in submarines and spacecrafts.]

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