InterviewSolution
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InterviewSolution
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The combustion of benzene (l) gives `CO_(2)(g)`and `H_(2)O(l) `. Given that heat of combustion of benzene at constant volumeis `- 3263.9 Kj mol^(-1)` at `25^(@)C`, heatof combustion ( in kJ `mol^(-1))`of benzene at constant pressure will be`( R = 8.314 JK^(-1) mol^(-1))`A. 4152.6B. `-452.46`C. `3260`D. `-3267.6` |
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Answer» Correct Answer - D `C_(6)H_(6)(l) +(15)/(2)O_(2)(g) rarr6CO_(2)(g)+3H_(2)O(l)` `Deltan_(g)= 6 - ( 15)/( 2) = - (3)/(2)` `DeltaH = DeltaU+ Deltan_(g) RT` `= - 3263.9 + ( - (3)/(2)) xx ( 8.314 xx 10^(-3)) xx ( 298)` `= - 3263.9 + ( -3.71)= - 3267 .6 kJ mol^(-1)` |
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