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The common difference of the AP \(\frac{1}{3},\frac{1-3b}{3},\frac{1-6b}{3},.....\) is(a) 1/3(b) -1/3(c) b(d) -b |
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Answer» Correct anwser is (d) -b The given AP is \(\frac{1}{3},\frac{1-3b}{3},\frac{1-6b}{3},.....\) ∴ Common difference, d = \(\frac{1-3b}{3}-\frac{1}{3}=\frac{1-3b-1}{3}=\frac{-3b}{3}=-b\) |
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