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The compoistion of `N_(2)O_(5)` is a first order reaction represented by: `N_(2)O_(5) rarr N_(2)O_(4) + 1//2O_(2)`. After `20 min` the volume of `O_(2)` profuced is `10 mL` and at the end of the reaction `40 mL`. The rate constant is equal toA. `(1)/(20)ln.(30)/(50)`B. `(1)/(20)ln.(50)/(30)`C. `(1)/(20)ln.(50)/(40)`D. `(1)/(20)ln.(40)/(30)` |
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Answer» Correct Answer - D `k = (2.303)/(t)log.(V_(oo))/(V_(oo)-V_(t))` or `k = (1)/(t)ln.(V_(oo))/(V_(oo)-V_(t))` `k = (1)/(20) ln.(40)/((40-10))` `= (1)/(20) ln.(40)/(30)` |
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