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The compound interest on ₹ 4000 at 10% per annum for 2 years 3 months , compounded annually, is(a) ₹ 916 (b) ₹ 900 (c) ₹ 961 (d) ₹ 896 |
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Answer» (c) ₹ 961 Explanation: Present value= ₹ 4000 Interest rate= 10% per annum Time=2 ¼ years To find the amount we have the formula, Amount (A) = P (1+(R/100))n Where P is present value, r is rate of interest, n is time in years. Now substituting the values in above formula we get, ∴ A = 4000 (1 + 10/100)2 [1 + (10/4)/100] ⇒ A = 4000 (1+1/10)2(1+ (5/2)/100) ⇒ A = 4000 (121/100) (41/40) ⇒ A = 121 × 41 ⇒ A = ₹ 4961 ∴ Compound interest = A – P = 4961 – 4000= ₹ 961 |
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