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The conversion of `A rarr B` follows second-order kinetics. Doubling the concentration of `A` will increase the rate of formation of `B` by a factorA. `1//4`B. 2C. `1//2`D. 4 |
Answer» Correct Answer - d `r = k (A)^(2)` , when concentration is doubled `r = k (2A)^(2) = k 4(A)^(2)` the rate becomes 4 times . |
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