The current gain in the common emitter mode of a transistor is 10. The input impedance is `20kOmega` and load of resistance is `100k Omega`. The power gain isA. 300B. 500C. 200D. 100

The current gain in the common emitter mode of a transistor is 10. The

1.	The current gain in the common emitter mode of a transistor is 10. The input impedance is `20kOmega` and load of resistance is `100k Omega`. The power gain isA. 300B. 500C. 200D. 100
Answer» Correct Answer - B The power gain is defined as the ratio of charge in output power to the charge in input power. Since, `P=Vi` therefore Power gain = current gain `xx` voltage gain `=beta xx beta ((R_("out"))/(R_("in")))=beta^(2)((R_("out"))/(R_("in")))` Given, `beta=10, R_("in") =20kOmega and R_("out")=100kOmega` `therefore" Power gain"=(10)^(2)((100)/(20))=100xx5=500`

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The current gain in the common emitter mode of a transistor is 10. The input impedance is `20kOmega` and load of resistance is `100k Omega`. The power gain isA. 300B. 500C. 200D. 100

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