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The current gain of a common base transistor circuit is 0.96. On changing the emitter current by 10.0 mA, the change in the base current will beA. 9.6 mAB. 0.4 mAC. 19.6 mAD. 24 mA |
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Answer» Correct Answer - A Current gain for common base transistor `alpha=((DeltaI_(C))/(DeltaI_(E)))_(VC)` Given, `alpha=0.96, DeltaI_(E)=10.0mA` `0.96=(DeltaI_(C))/(10.0)` `DeltaI_(C)=0.96xx10.0=9.6mA` |
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