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The current I through `10Omega` resistor in the circuit given below is A. 50 mAB. 20 mAC. 40 mAD. 80 mA

Answer» Correct Answer - D
Here, diode `D_(2)` is reverse biased while `D_(1)` is forward biase (d) So, no current flows across `D_(2)`, current flows through diode `D_(1)`.
`I=(V)/(R )=(2)/(10+15)=(2)/(25)=0.08A=80mA`


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