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The current in a wire varies with time according to(d) 42 C.the equation I = 4 + 21, where I is in ampere and tis in second. The quantity of charge which has to bepassed through a cross-section of the wire duringthe time t = 2 s to t = 6 s is(a) 40 C (b) 48 C (c) 38 C (d) 43 C |
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Answer» Integrate I dt from t=2 to t=6swe get Q= 4×4+36-4=48Coption B 0ption B is the right answer option B is the correct answer |
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