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The current in the following circuit is |
Answer» ExplanationFrom the given FIGURE, the resistance in the arms AC and BC are given in series R' = Rᴀᴄ = + Rʙᴄ R' = 3Ω + 3Ω = 6Ω Now, R' is in parallel with the resistance in ARM AB, So, R = R' × Rᴀʙ/ R' + R'ᴀʙ = 6Ω × 3Ω/6Ω + 3Ω = 2Ω Therefore, the OHMS law can be stated as V = i R or current, i = V/R Substituting the values, we get i = 2/2 = 1A ( ∵ V = 2V) ∴ The current in the following circuit is 1 A ! |
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