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The deacy time `t` for radioactive element proceeds to `4` half-lives. The total decay time `(t)` in terms of average life `(T)` is given by:A. `t = 27` In `2`B. `t = 4T` In `2`C. `t = 27^(4)` In `2`D. `(1)/(T^(2))` In `2` |
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Answer» Correct Answer - `(b)` `t = 4xx t_(1//2)` Also `t_(1//2) = (0.693)/(lambda) = 0.693xx T` `:. t = 4xx0.693xx T` `= 4T` in `2` |
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