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The decomposition of `A` into product has value of `k` as `4.5xx10^(3)s^(-1)` at `10^(@)C` and energy of activation of `60kJmol^(-1)`. At what temperature would `k` be `1.5xx10^(4)s^(-1)?`A. 273.15 kB. `24.01^@C`C. 280.39 KD. `45.29^@C` |
Answer» Correct Answer - B According to Arrhenius equation, `"log"(k_(2))/(k_(1))=E_(a)/(2.303R)xx(T_(2)-T_(1))/(T_(1)T_(2))` `"log"(1.5xx10^(4))/(4.5xx10^(3))=(60000J"mol"^(-1))/(2.303xx(8.314J"mol"^(-1)))((T_(2)-283)/(283T_(2)))` `log3.333=3.1333.62((T_(2)-283)/(283T_(2)))` `T_(2)=297.01k=(297.01-273.0)^@C=24.01^@C` Temperature =`24.01^@C` |
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