The degree of association `(alpha)` is given by the expressionA. `alpha=(i-1)/(1/n-1)`B. `alpha=(i-1)/(n-1)`C. `alpha=(1-i)/(1/n-1)`D. `alpha=(1-i)/(n-1)`

The degree of association `(alpha)` is given by the expressionA. `alph

1.	The degree of association `(alpha)` is given by the expressionA. `alpha=(i-1)/(1/n-1)`B. `alpha=(i-1)/(n-1)`C. `alpha=(1-i)/(1/n-1)`D. `alpha=(1-i)/(n-1)`
Answer» Correct Answer - 3 Degree of association `(alpha)` is the fraction of one mole of solute which associates to form bigger particle:- `nA hArr (A)_(n)` moles 1 mol 0 mol before assocation Moles `(1 - alpha)` mol `((alpha)/(n))` mole after associates `i=("Molar after association")/("Moles before association")` `=((1-alpha)+(alpha/n))/1=(1+(1/n-1)alpha)/1` or `(1/n-1)alpha=i-1` `alpha=(i-1)/((1/n-1))` For dissociation `alpha=(i-1)/(n-1)`

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The degree of association `(alpha)` is given by the expressionA. `alpha=(i-1)/(1/n-1)`B. `alpha=(i-1)/(n-1)`C. `alpha=(1-i)/(1/n-1)`D. `alpha=(1-i)/(n-1)`

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