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the density of a non-uniform rod of length 1 m is given by `rho(x)=a(1+bx^(2))` where ,a and b are constants and `0lexle1,` the centre of mass of the rod will be at.A. `(3(2+b))/(4(3+b))`B. `(4(2+b))/(3(3+b))`C. `(3(3+b))/(4(2+b))`D. `(4(3+b))/(3(2+b))` |
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Answer» Correct Answer - a density is given as `rho (x)=a(1+bx^(2))` where a and b are constants and `0 le xle 1.` Let `b to 0,` in this case ` rho (x)=a=` constant Hence ,centre of mass will be at `x=0.5 m` (middle of the rod) Putting , b=0 in the options , only (A) given 0.5 Note :- We should not check options by puting a = 0 , because ` rho =0` for `a =0` |
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