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Calculate the velocity with which a solid cylinder rolls down an inclined plane of height `10m` with slipping (take `g=10m//s^(2)`) |
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Answer» `M.I.` of solid cylinder `=(1)/(2)MR^(2)` `K=(1)/(sqrt(2))R` `v=sqrt((2xx10xx10)/((1+(1)/(2))))=sqrt((2xx10xx10xx2)/(3))=(20)/(sqrt(3))m//s` Hint : `v=sqrt((2gh)/((1+(k^(2))/(R^(2)))))` |
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