A torque of `5Nm` is applied on a particle for `2` seconds, calculate – InterviewSolution

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1.	A torque of `5Nm` is applied on a particle for `2` seconds, calculate the change in its angular momentum.
Answer» `(dL)/(dt)=vectau` `impliesdL=2xx5=10kgm^(2)//s` Hint. `vectau=(dvecL)/(dt)`

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