A force `(hati-2hatj+3hatk)` acts on a particle of position vector `(3 – InterviewSolution

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1.	A force `(hati-2hatj+3hatk)` acts on a particle of position vector `(3hati+2hatj+hatk)`. Calculate the `hatj^(th)` component of the torque acting on the particle.
Answer» `vectau=vecrxxvecF` `=\|{:(hati,hatj,hatk),(3,2,1),(1,-2,3):}\|=hati(6+2)+hatj(1-9)hatk(-6-2)` `=8hati-8hatj-8hatk` `=8(hati-hatj-hatk)` The `hatj^(th)` component of the torque is `-8`

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