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The derivative of log|x| isA. `(1)/(x), x gt 0`B. `(1)/(|x|), x ne 0`C. `(1)/(x), x ne 0`D. None of these

Answer» Correct Answer - C
We have `y=log|x|={{:(,log x,x gt0),(,log(-x),x lt ):}`
`therefore (dy)/(dx)={{:(,(1)/(x), x gt0),(,(1)/(-x)(-1)=(1)/(x),x lt 0):}`
`Rightarrow (dy)/(dx)=(1)/(x), x ne 0`


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