1.

The diameter if a soap bubble is 5cm.The excess pressure inside the bubble is 2bar.Find the surface tension of the surface film of the bubble.

Answer»

\mathtt{\huge\fbox{Solution :}}

Given,

  • Diameter of soap bubble = 5 cm

So, radius of soap bubble = 2.5 cm = 0.025 m

The excess pressure inside the bubble = 2 bar

We know that, the excess pressure inside the bubble is given by

\large{\mathtt{ \underline{\fbox{p_{i} -p _{o}  =  \frac{2t}{r} }}}}

Where,

  • (Pi - PO) is excess pressure inside the soap bubble
  • t is the surface tension
  • r is the radius of soap bubble

Substitute the known values , we get

\sf \mapsto2 =  \frac{2t}{0.025}  \\  \\\sf \mapsto  t = 0.025 \: newton \: per \: meter

HENCE, the surface tension is 0.025 newton/meter



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