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The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions moving monce over to level a playground. What is the area of the playground? |
Answer» Given, Diameter of roller = 84 cm Radius of roller = \(\frac{84}{2}\) = 42 cm Length of roller = 120 cm So, Curved surface area of roller = 2πrh = 2 x \(\frac{22}{7}\) x 42 x 120 = 31680 cm2 No. of revolution it takes to level the ground = 500 given Hence, Area of play ground = 500 × 31680 = 15840000 cm2 = 1584 m2 |
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