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The difference between `Delta H` and `Delta U` for the combustion of methane at `27^(@)C` will be (in `J mol^(-1)`)A. `8.314 xx 27 xx - 3`B. `8.314 xx 300 xx (-3)`C. `8.314 xx 300 xx (-2)`D. `8.314 xx 300 xx1` |
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Answer» Correct Answer - C Thermochemical equaiton for the combustion of methane is `CH_(4) (g) + 2 O_(g) rarr CO_(2) (g) + 2H_(2) O (1)` According to thermodynamics, `Delta H = Delta U + Delta n_(g) RT` or `Delta H - Delta U = Delta n_(g) RT` Where `Delta n_(g) = sum n_(P) (g) - sum n_(R ) (g)` `= (1) - (1 + 2)` `= - 2` `:. Delta - Delta U = (-2) (8.314) (300)` |
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