The Difference Of Two Numbers Is 14. Their Lcm And Hcf Are 441 And 7.

1.	The Difference Of Two Numbers Is 14. Their Lcm And Hcf Are 441 And 7. Find The Two Numbers ?
Answer» SINCE their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y Difference = 14 => 7x - 7y = 14 => X - y = 2 product of numbers = product of their hcf and lcm => 7x * 7y = 441 * 7 => x * y = 63 Now, we have x * y = 63 , x - y = 2 => x = 9 , y = 7 The numbers are 7x and 7y => 63 and 49. Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y Difference = 14 => 7x - 7y = 14 => x - y = 2 product of numbers = product of their hcf and lcm => 7x * 7y = 441 * 7 => x * y = 63 Now, we have x * y = 63 , x - y = 2 => x = 9 , y = 7 The numbers are 7x and 7y => 63 and 49.

The Difference Of Two Numbers Is 14. Their Lcm And Hcf Are 441 And 7. Find The Two Numbers ?

Answer»

SINCE their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y

Difference = 14

=> 7x - 7y = 14

=> X - y = 2

product of numbers = product of their hcf and lcm

=> 7x * 7y = 441 * 7

=> x * y = 63

Now, we have

x * y = 63 , x - y = 2

=> x = 9 , y = 7

The numbers are 7x and 7y

=> 63 and 49.

Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y